Return nil if nothing matched - RefactorMyCode.com

I want to return nil if nothing matched and the second item in the resulting array if matched. How can i write this more elegant?

def parse_url(url)
  matches = url.match(/\/([\d]{10})/)
  return nil unless matches
  matches[1]
end

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def parse_url(url)
  url[/\/([\d]{10})/, 1]
end

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[\d] same as \d

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def parse_url(url)
  url[/\/(\d{10})/, 1]
end

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